How do you factor by grouping $m z - 5 m h^{2} - 5 n z + 25 n h^{2}$ $mz-5mh^2-5nz+25nh^2$ ?

Question

3993 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-13T07:20:44

We can factorise the expression by making groups of 2:

$(m z - 5 m h^{2}) - (5 n z - 25 n h^{2})$ $(mz-5mh^2)-(5nz-25nh^2)$

$m$ $m$ is factor common to both the terms in the first group, and $5 n$ $5n$ is common to both the terms in the second group

$= m (z - 5 h^{2}) - 5 n (z - 5 h^{2})$ $= m(z - 5h^2) - 5n(z - 5h^2)$

$z - 5 h^{2}$ $z - 5h^2$ is common to both the terms in the expression

$= (z - 5 h^{2}) (m - 5 n)$ $= color(green)( (z - 5h^2)(m-5n)$

How do you factor by grouping mz−5mh2−5nz+25nh2mz-5mh^2-5nz+25nh^2?