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How do you factor by grouping #m^3 + 3m^2n + 3mn^2 +n^3#?

1 Answer

May 14, 2015

#m^3+n^3 +3mn (m+n)#

= #(m+n)(m^2 -mn +n^2)+3mn(m+n)#

= #(m+n)(m^2-mn+n^2 +3mn)#

= #(m+n)(m^2+2mn+n^2)#

= #(m+n)(m+n)^2#

= #(m+n)^3#

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