How do you factor by grouping $c^{3} + 3 c^{2} - 9 c - 27$ $c^3+3c^2-9c-27$ ?

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Answer 1 · 2015-05-14T18:08:53

$f (c) = c^{2} (c + 3) - 9 (c + 3) = (c + 3) (c^{2} - 9)$ $f(c) = c^2(c + 3) - 9(c + 3) = (c + 3) (c^2 - 9)$

$= {(c + 3)}^{2} (c - 3)$ $= (c + 3)^2(c - 3)$

How do you factor by grouping c3+3c2−9c−27c^3+3c^2-9c-27?