How do you factor by grouping #9x^2 + 3xy + 3x + y#? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer George C. May 23, 2015 #9x^2+3xy+3x+y# #= (9x^2+3xy)+(3x+y)# #= 3x(3x+y)+(3x+y)# #= (3x+1)(3x+y)# Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 1769 views around the world You can reuse this answer Creative Commons License