How do you factor by grouping $9 x^{2} + 3 x y + 3 x + y$ $9x^2 + 3xy + 3x + y$ ?

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Answer 1 · 2015-05-22T07:23:13

$9 x^{2} + 3 x y + 3 x + y$ $9x^2 + 3xy + 3x + y$

We can make groups of two to factorise this expression:
$9 x^{2} + 3 x + 3 x y + y$ $color(blue)(9x^2 +3x) + color(red)(3xy +y)$

$3 x$ $color(blue)(3x$ is common to both the terms in the first group, and $y$ $color(red)(y$ is common to both the terms in the second group:

We can write the expression as :
$3 x (3 x + 1) + y (3 x + 1)$ $3x(3x +1) + y(3x +1)$

$= (3 x + y) (3 x + 1)$ $=color(green)((3x+y)(3x+1)$ , is the factorised form.

How do you factor by grouping 9x^2 + 3xy + 3x + y9x2+3xy+3x+y9x^2 + 3xy + 3x + y?