How do you factor by grouping $8 s t + 28 t - 10 s - 35$ $8st+28t-10s-35$ ?

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Answer 1 · 2015-04-10T10:08:18

We can factorize the expression by forming groups of 2 terms.

$8 s t + 28 t - 10 s - 35$ $8st+28t-10s-35$

$= (8 s t + 28 t) + (- 10 s - 35)$ $= (8st+28t)+(-10s-35)$

$4 t$ $4t$ is a common factor in the first group, and $- 5$ $-5$ is a common factor in the second.

$= 4 t (2 s + 7) + (- 5) \cdot (2 s + 7)$ $= 4t(2s+7) + (-5)*(2s+7)$

$= (2 s + 7) \cdot (4 t - 5)$ $color(green)( = (2s+7) * (4t - 5)$ is the factorised form of $8 s t + 28 t - 10 s - 35$ $8st+28t-10s-35$

How do you factor by grouping 8st+28t−10s−358st+28t-10s-35?