How do you factor by grouping: $8st+12t-10s-15$ ?

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Answer 1 · 2015-04-21T12:34:20

You can try collecting $2s$ from the first and third term and $3$ from the second and fourth:
$2s(4t-5)+3(4t-5)=$
$(4t-5)(2s+3)$

How do you factor by grouping: 8st+12t-10s-158st+12t-10s-15?