How do you factor by grouping 7-2x^5-3+2+127−2x5−3+2+12? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer Dr. K. · Jacobi J. Jul 11, 2018 2(9-x^5)2(9−x5) Explanation: 7 - 2x^5-3+2+127−2x5−3+2+12 =7-3+2+12 - 2x^57−3+2+12−2x5 simplify the numbers = 18- 2x^518−2x5 =(2xx9)-(2xxx^5)(2×9)−(2×x5) find common factor =2(9-x^5)2(9−x5) factor out 2 Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor 2x+2y+ax+ay2x+2y+ax+ay? How do you factor 3x^2+8x+43x2+8x+4 by using the grouping method? How do you factor 6x^2-9x+10x-156x2−9x+10x−15? How do you group and factor 4jk-8j^2+5k-10j4jk−8j2+5k−10j? What are the factors of 2m^3+3m^2+4m+62m3+3m2+4m+6? How do you factor quadratics by using the grouping method? How do you factor x^4-2x^3+5x-10x4−2x3+5x−10? See all questions in Factoring by Grouping Impact of this question 2013 views around the world You can reuse this answer Creative Commons License