How do you factor by grouping $63 n^{3} + 54 n^{2} - 105 n - 90$ $63n^3 + 54n^2 - 105n - 90$ ?

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How do you factor by grouping $63 n^{3} + 54 n^{2} - 105 n - 90$ $63n^3 + 54n^2 - 105n - 90$ ?

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Answer 1 · 2018-05-10T17:44:05

$3 (7 n + 6) (3 n^{2} - 5)$ $3(7n+6)(3n^2-5)$

Explanation:

$take out a common factor 3$ $"take out a "color(blue)"common factor "3$

$= 3 (21 n^{3} + 18 n^{2} - 35 n - 30)$ $=3(21n^3+18n^2-35n-30)$

$= 3 (3 n^{2} (7 n + 6) - 5 (3 n + 6))$ $=3(color(red)(3n^2)(7n+6)color(red)(-5)(3n+6))$

$= 3 ((7 n + 6) (3 n^{2} - 5))$ $=3((7n+6)(color(red)(3n^2-5)))$

$= 3 (7 n + 6) (3 n^{2} - 5)$ $=3(7n+6)(3n^2-5)$

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How do you factor by grouping $63 n^{3} + 54 n^{2} - 105 n - 90$ $63n^3 + 54n^2 - 105n - 90$ ?

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How do you factor by grouping 63n3+54n2−105n−9063n^3 + 54n^2 - 105n - 90?

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How do you factor by grouping $63 n^{3} + 54 n^{2} - 105 n - 90$ $63n^3 + 54n^2 - 105n - 90$ ?