How do you factor by grouping $6 - 3 x - 2 y + x y$ $6-3x-2y+xy$ ?

Question

2999 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-17T07:56:22

$6 - 3 x - 2 y + x y$ $6 - 3x - 2y + xy$

We factor this expression by making groups of 2 terms
$= (6 - 3 x) + (x y - 2 y)$ $= (6 - 3x) + (xy - 2y)$

Now we take the common factors out from each group
$= 3 (2 - x) - y (2 - x)$ $= 3( 2-x) - y(2 - x)$

$(2 - x)$ $( 2-x)$ is a common factor to each of the terms now,

$= (2 - x) (3 - y)$ $= (2-x)(3-y)$

$(2 - x) (3 - y)$ $color(green)( (2-x)(3-y))$ is the Factorised form of $6 - 3 x - 2 y + x y$ $6 - 3x - 2y + xy$

How do you factor by grouping 6−3x−2y+xy6-3x-2y+xy?