How do you factor by grouping 4z^2+12z-az-3a4z2+12z−az−3a?
1 Answer
Apr 13, 2015
(4z-a)(z+3)
Make groups as (4
4z(z+3) -a(z+3).Since z+3 is common to both the terms now, we can again take out the common factor to become (z+3)(4z-a).