How do you factor by grouping $4+9xy-18y-2x$ ?

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Answer 1 · 2018-05-30T17:28:50

$(x-2)(9y-2)$

$4+9xy-18y-2x$

group the terms like this:

$9xy-18y-2x + 4$

now factor $9y$ out of the first 2 terms:

$9y(x-2)-2x + 4$

then factor $-2$ out of the other 2 terms:

$9y(x-2)-2(x -2)$

Finally factor out the $(x-2)$ like this:

$(x-2)(9y-2)$

How do you factor by grouping 4+9xy-18y-2x4+9xy-18y-2x?