How do you factor by grouping # 3x^4+6x^3-6x-12 #?

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How do you factor by grouping # 3x^4+6x^3-6x-12 #?

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Answer 1 · 2015-05-20T19:30:27

You can collect #3x# from the first and third term and #6# from the second and fourth to get:
#3x(x^3-2)+6(x^3-2)=# now collect #(x^3-2)# and get:
#=(x^3-2)(3x+6)#

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How do you factor by grouping # 3x^4+6x^3-6x-12 #?

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