How do you factor by grouping $3n^2 - 8n + 4$ ?

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How do you factor by grouping $3n^2 - 8n + 4$ ?

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Answer 1 · 2015-05-17T12:05:08

$3n^2-8n+4$

$= 3n^2 - 2n - 6n + 4$

$= (3n^2-2n) - (6n-4)$

$= n(3n-2) - 2(3n-2)$

$= (n-2)(3n-2)$

The 'trick' was to split the original $-8n$ term into two parts such that the resulting ratio of the first and second terms $3n^2$ and $-2n$ was the same as the ratio of the third and fourth terms $-6n$ and $4$ .

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How do you factor by grouping $3n^2 - 8n + 4$ ?

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