How do you factor by grouping $3bc-4ad+6ac-2bd$ ?

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Answer 1 · 2015-10-13T17:05:54

Group terms with common factors and separate out those factors to find:

$3bc-4ad+6ac-2bd = (b+2a)(3c-2d)$

$3bc-4ad+6ac-2bd = (3bc-2bd) + (6ac-4ad)$

$= b(3c-2d)+2a(3c-2d) = (b+2a)(3c-2d)$

How do you factor by grouping 3bc-4ad+6ac-2bd3bc-4ad+6ac-2bd ?