How do you factor by grouping $3 a x - 3 b x - a y + b y$ $3ax - 3bx - ay + by$ ?

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How do you factor by grouping $3 a x - 3 b x - a y + b y$ $3ax - 3bx - ay + by$ ?

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Answer 1 · 2018-03-27T07:06:39

$(a - b) (3 x - y)$ $(a-b)(3x-y)$

Explanation:

$consider the expression as two groups$ $"consider the expression as two groups"$

$[3 a x - 3 b x] + [- a y + b y]$ $[3ax-3bx]+[-ay+by]$

$factorise each 'group'$ $"factorise each 'group'"$

$3 x (a - b) - y (a - b)$ $color(red)(3x)(a-b)color(red)(-y)(a-b)$

$take out the common factor (a - b)$ $"take out the common factor "(a-b)$

$(a - b) (3 x - y)$ $(a-b)(color(red)(3x-y))$

$\Rightarrow 3 a x - 3 b x - a y + b y = (a - b) (3 x - y)$ $rArr3ax-3bx-ay+by=(a-b)(3x-y)$

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How do you factor by grouping $3 a x - 3 b x - a y + b y$ $3ax - 3bx - ay + by$ ?

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How do you factor by grouping 3ax−3bx−ay+by3ax - 3bx - ay + by?

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How do you factor by grouping $3 a x - 3 b x - a y + b y$ $3ax - 3bx - ay + by$ ?