How do you factor by grouping: $2x^3 + 8x^2 - 7x – 28$ ?

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Answer 1 · 2018-03-25T20:39:36

$(x+4)(2x^2-7)$

$2x^3+8^2-7x-28=0$

$2x^2(x+4)-7(x+4)=0$

$(x+4)(2x^2-7)=0$

How do you factor by grouping: 2x^3 + 8x^2 - 7x – 282x^3 + 8x^2 - 7x – 28?