How do you factor by grouping: $2x^2 - 6x + 3x - 9$ ?

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Answer 1 · 2018-04-18T22:58:08

$(2x+3)(x-3)$

We have four terms; thus, we'll need to make two groups of two terms and factor each group. Group together as follows:

$(2x^2-6x)+(3x-9)$

$2x^2-6x=2x(x-3)$

$3x-9=3(x-3)$

We then rewrite as

$2x(x-3)+3(x-3)$

Factoring out $(x-3)$ from this, we get

$(2x+3)(x-3)$

How do you factor by grouping: 2x^2 - 6x + 3x - 92x^2 - 6x + 3x - 9?