How do you factor by grouping $224 a z + 56 a c - 84 y z - 21 y c$ $224az+56ac-84yz-21yc$ ?

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Answer 1 · 2015-05-17T20:39:13

First notice that all the coefficients are divisible by 7, so let's separate out that factor first...

$224 a z + 56 a c - 84 y z - 21 y c$ $224az+56ac-84yz-21yc$

$= 7 (32 a z + 8 a c - 12 y z - 3 y c)$ $= 7(32az+8ac-12yz-3yc)$

$= 7 ((32 a z + 8 a c) - (12 y z + 3 y c))$ $= 7((32az+8ac)-(12yz+3yc))$

$= 7 (8 a (4 z + c) - 3 y (4 z + c))$ $= 7(8a(4z+c)-3y(4z+c))$

$= 7 (8 a - 3 y) (4 z + c)$ $= 7(8a-3y)(4z+c)$

How do you factor by grouping 224az+56ac-84yz-21yc224az+56ac−84yz−21yc224az+56ac-84yz-21yc?