How do you factor by grouping $−15abc − 15ac^2 + 3bc + 3c^2$ ?

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Answer 1 · 2015-04-29T11:12:27

$−15abc − 15ac^2 + 3bc + 3c^2$

We can factor this expression by making groups of 2 terms

$= (−15abc − 15ac^2) + (3bc + 3c^2)$

Now we take the common factors out from each group

$= -15ac(b + c) + 3c(b+c)$

$(b+c)$ is a common factor to each of the terms now

$= (b+c)(-15ac + 3c)$

$= (b+c)(3c - 15ac )$

The factor $3c$ is common to the terms in the second group above

$= (b+c){3c(1 - 5a)}$

$=color(green)( 3c(b+c)(1-5a)$ is the Factorised form of $−15abc − 15ac^2 + 3bc + 3c^2$

How do you factor by grouping −15abc − 15ac^2 + 3bc + 3c^2−15abc − 15ac^2 + 3bc + 3c^2?