How do you factor by grouping $12xy- 8x + 42y - 28$ ?

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Answer 1 · 2015-05-17T07:44:22

$12 xy - 8x + 42y -28$

We factor this expression by making groups of 2 terms
$= (12xy - 8x) + (42y - 28)$

Now we take the common factors out from each group
$= 4x( 3y -2) + 14(3y -2)$

$( 3y -2)$ is a common factor to each of the terms now:
$= (3y -2)(4x +14)$

$2$ is common to the terms in the second group above
$= (3y -2){2(2x+ 7)}$

$color(green)( (3y -2){2(2x+ 7)}$ is the Factorised form of $12 xy - 8x + 42y -28$

How do you factor by grouping 12xy- 8x + 42y - 2812xy- 8x + 42y - 28?