How do you factor by grouping $12 x y - 28 x - 15 y + 35$ $12xy-28x-15y+35$ ?

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Answer 1 · 2015-05-03T12:02:14

To factorise this expression, we make groups of 2

$(12 x y - 28 x) - (15 y - 35)$ $(12xy-28x)-(15y-35)$

$= 4 x (3 y - 7) - 5 (3 y - 7)$ $= 4x(3y-7) - 5(3y - 7)$

$3 y - 7$ $3y - 7$ is common to both the terms

$= (3 y - 7) (4 x - 5)$ $=color(green)( (3y - 7)(4x - 5)$

How do you factor by grouping 12xy−28x−15y+3512xy-28x-15y+35?