How do you factor and solve $r^{3} + 3 r^{2} + 3 r + 1 = 0$ $r^3 + 3r^2 + 3r + 1 = 0$ ?

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How do you factor and solve $r^{3} + 3 r^{2} + 3 r + 1 = 0$ $r^3 + 3r^2 + 3r + 1 = 0$ ?

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Answer 1 · 2017-01-12T14:16:17

r = -1

Explanation:

$f (r) = r^{3} + 3 r^{2} + 3 r + 1 = 0$ $f(r) = r^3 + 3r^2 + 3r + 1 = 0$
Use algebra identity:
${(r + 1)}^{3} = r^{3} + 3 r^{2} + 3 r + 1$ $(r + 1)^3 = r^3 + 3r^2 + 3r + 1$
$f (r) = {(r + 1)}^{3}$ $f(r) = (r + 1)^3$
Answer:
r = - 1

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How do you factor and solve $r^{3} + 3 r^{2} + 3 r + 1 = 0$ $r^3 + 3r^2 + 3r + 1 = 0$ ?

1 Answer

Explanation:

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How do you factor and solve $r^{3} + 3 r^{2} + 3 r + 1 = 0$ $r^3 + 3r^2 + 3r + 1 = 0$ ?