How do you factor and solve #r^2+8r+14=0#?

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How do you factor and solve #r^2+8r+14=0#?

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Answer 1 · 2016-07-12T14:10:09

#x = - 4 +- sqrt2#

Explanation:

Use the improved quadratic formula in graphic form (Google)
#y = r^2 + 8r + 14 = 0#
#D = d^2 = b^2 - 4ac = 64 - 56 = 8# --> #d = +- 2sqrt2#
There are 2 real roots:
#x = -b/(2a) +- d/(2a) = -8/2 +- (2sqrt2)/2 = - 4 +- sqrt2#
Factored form of y:
#y = (x - x1)(x - x2) = (x + 4 - sqrt2)(x + 4 + sqrt2)#

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How do you factor and solve #r^2+8r+14=0#?

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