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How do you factor #9x^2-121#?

1 Answer

May 1, 2015

Note that #9x^2 = (3x)^2#
and
#121 = 11^2#

So
#9x^2 -121# is the difference of two squares.

In its general form the difference of two squares:
#(a^2-b^2) = (a+b)(a-b)#

So
#9x^2-121#
# = (3x)^2-11^2#
# = (3x+11)(3x-11)#

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