How do you factor $8x^3 - 8x^2 - x + 1$ by grouping?

Question

How do you factor $8x^3 - 8x^2 - x + 1$ by grouping?

↳Redirected from "How do ionic compounds dissolve?"

1 Answer

Impact of this question

1999 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-09T09:01:37

$8x^3-8x^2-x+1$
Take $8x^2$ common from first two terms and $-1$ from the last two terms.
$=8x^2(x-1)-1(x-1)$
Take the factor $(x-1)$ as common.
$=(x-1)(8x^2-1)$

Science

Math

Humanities

... and beyond

How do you factor $8x^3 - 8x^2 - x + 1$ by grouping?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor 8x^3 - 8x^2 - x + 18x^3 - 8x^2 - x + 1 by grouping?

1 Answer

Related questions

Impact of this question

How do you factor $8x^3 - 8x^2 - x + 1$ by grouping?