How do you factor #8x^3 - 8x^2 - x + 1# by grouping?

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How do you factor #8x^3 - 8x^2 - x + 1# by grouping?

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Answer 1 · 2017-06-09T09:01:37

#8x^3-8x^2-x+1#
Take #8x^2# common from first two terms and #-1# from the last two terms.
#=8x^2(x-1)-1(x-1)#
Take the factor #(x-1)# as common.
#=(x-1)(8x^2-1)#

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How do you factor #8x^3 - 8x^2 - x + 1# by grouping?

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