How do you factor 8u^2 + 6u - 9?

1 Answer
Alan P. ยท George C.
Jun 16, 2015

8u^2+6u-9 = (2u+3)(4u-3)

Explanation:

We need to look at factors of
color(white)("XXXX") 8
color(white)("XXXX") (a,b) epsilon {(1,8), (2,4)}
and
color(white)("XXXX") (-9)
color(white)("XXXX")(c,d) epsilon {(1,-9), (-1,9), (3,-3), (-3,3)}

such that
color(white)("XXXX")ac - bd = +6

then plug them into
color(white)("XXXX")(au+c)(bu+d)

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