How do you factor $7 x^{3} - 21 x^{2} - 2 x + 6$ $7x^3 - 21x^2 - 2x + 6$ by grouping?

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How do you factor $7 x^{3} - 21 x^{2} - 2 x + 6$ $7x^3 - 21x^2 - 2x + 6$ by grouping?

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Answer 1 · 2016-05-31T23:56:05

$(x - 3) (\sqrt{7} x - \sqrt{2}) (\sqrt{7} x + \sqrt{2})$ $(x - 3)(sqrt7x - sqrt2)(sqrt7x + sqrt2)$

Explanation:

$f (x) = 7 x^{2} (x - 3) - 2 (x - 3)$ $f(x) = 7x^2(x - 3) - 2(x - 3)$
$f (x) = (x - 3) (7 x^{2} - 2)$ $f(x) = (x - 3)(7x^2 - 2)$
$f (x) = (x - 3) (\sqrt{7} x - \sqrt{2}) (\sqrt{7} x + \sqrt{2})$ $f(x) = (x - 3)(sqrt7x - sqrt2)(sqrt7x + sqrt2)$

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How do you factor $7 x^{3} - 21 x^{2} - 2 x + 6$ $7x^3 - 21x^2 - 2x + 6$ by grouping?

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How do you factor $7 x^{3} - 21 x^{2} - 2 x + 6$ $7x^3 - 21x^2 - 2x + 6$ by grouping?