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How do you factor #7x+28x^2-35x^3#?

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1 Answer

iceman · EZ as pi

Feb 16, 2017

#-7x(5x+1)(x-1)#

Explanation:

#7x+28x^2-35x^3# => factor GCF:

Note that dividing by #-7x# makes a positive #x^2# term.

#-7x(5x^2-4x-1)#
#-7x(5x^2-5x+x-1)#
#-7x[5x(x-1)+(x-1)]#
#-7x(x-1)(5x+1)#

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