How do you factor 6c^2-24d^2? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Alan P. May 7, 2015 Remember the general difference of squares: x^2-y^2=(x+y)(x-y) 6c^2-24d^2 = 6(c^2-(2d)^2) =6(c+2d)(c-2d) Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor x^3 -8? What are the factors of x^3y^6 – 64? How do you know if x^2 + 10x + 25 is a perfect square? How do you write 16x^2 – 48x + 36 as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor 16x^2-36 using the difference of squares? How do you factor 2x^4y^2-32? How do you factor x^2 - 27? See all questions in Factor Polynomials Using Special Products Impact of this question 1462 views around the world You can reuse this answer Creative Commons License