How do you factor 6ap+15a−4p−10?
1 Answer
May 9, 2017
Explanation:
separate the terms into 2 groups
6ap+15a and −4p−10
factorise each group by taking out a common factor
3a(2p+5) and −2(2p+5)
putting this together gives us
3a(2p+5)−2(2p+5)
take out the common factor (2p+5)
(2p+5)(3a−2)
⇒6ap+15a−4p−10=(2p+5)(3a−2)