How do you factor $5 x^{3} + 4 x^{2} - 10 x - 8$ $5x^3+4x^2-10x-8$ by grouping?

Question

3066 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-07T14:03:32

$(x^{2} - 2) (5 x + 4)$ $(x^2-2)(5x+4)$

Let $p (x) = 5 x^{3} + 4 x^{2} - 10 x - 8$ $p(x)=5x^3+4x^2-10x-8$

$=ul(5x^3-10x)+ul(4x^2-8)$

$=5x(x^2-2)+4(x^2-2)$

$=(x^2-2)(5x+4)$

How do you factor 5x^3+4x^2-10x-8 5x3+4x2−10x−85x^3+4x^2-10x-8 by grouping?