How do you factor $4x^2 + 20x + 5y +xy$ ?

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Answer 1 · 2015-04-15T18:16:53

Factor by grouping:

$4x^2 + 20x + 5y +xy = (4x^2 + 20x) + (5y +xy)$

$= 4x(x+5)+y(5+x) = 4x(x+5)+y(x+5)$

$= (4x+y)(x+5)$

How do you factor 4x^2 + 20x + 5y +xy4x^2 + 20x + 5y +xy?