How do you factor $3 y z^{2} - 4 y^{2} z + 6 y^{3} - 2 z^{3}$ $3yz^2 -4y^2z+6y^3-2z^3$ ?

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How do you factor $3 y z^{2} - 4 y^{2} z + 6 y^{3} - 2 z^{3}$ $3yz^2 -4y^2z+6y^3-2z^3$ ?

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Answer 1 · 2016-02-21T20:28:47

It is

$3 y z^{2} - 4 y^{2} z + 6 y^{3} - 2 z^{3} = 3 y \cdot (z^{2} + 2 y^{2}) - 2 z \cdot (2 y^{2} + z^{2}) = (3 y - 2 z) \cdot (z^{2} + 2 y^{2})$ $3yz^2 -4y^2z+6y^3-2z^3=3y*(z^2+2y^2)-2z*(2y^2+z^2)=(3y-2z)*(z^2+2y^2)$

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How do you factor $3 y z^{2} - 4 y^{2} z + 6 y^{3} - 2 z^{3}$ $3yz^2 -4y^2z+6y^3-2z^3$ ?

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How do you factor $3 y z^{2} - 4 y^{2} z + 6 y^{3} - 2 z^{3}$ $3yz^2 -4y^2z+6y^3-2z^3$ ?