How do you factor #3x^2 - 8x = -4#?

1 Answer
Jim G.
Jul 15, 2018

#(x-2)(3x-2)=0#

Explanation:

#"add 4 to both sides"#

#3x^2-8x+4=0larrcolor(blue)"in standard form"#

#"using the a-c method to factor the quadratic"#

#"the factors of the product "3xx4=12#

#"which sum to "-8" are "-6" and "-2#

#"split the middle term using these factors"#

#3x^2-6x-2x+4=0larrcolor(blue)"factor by grouping"#

#color(red)(3x)(x-2)color(red)(-2)(x-2)=0#

#"take out the "color(blue)"common factor "(x-2)#

#(x-2)(color(red)(3x-2))=0#

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