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How do you factor #3x²-12xy-63y²#?

1 Answer

Jun 3, 2015

Given #3x^2-12xy-63y^2#

Extract the obvious common numeric factor #3#
#color(white)("XXXX")##=3(x^2-4xy-21)#

#21# can be factored as #3xx7# and #3-7 = -4#
so
#color(white)("XXXX")##=3(x+3)(x-7)#

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