How do you factor #-3ax^2p + 24pa + 6axp#?

1 Answer
EZ as pi
Sep 19, 2016

# -3ap(x-4)(x+2)#

Explanation:

Always look for a common factor first, then look again.

#-3ax^2p + 24pa + 6axp#

It is better to have the negative sign at the front rather than a #-x^2 # term inside the bracket.

=#-3ap(x^2 -8-2x)" "larr# re-arrange the terms

=#-3ap(x^2 -2x -8)" "larr# find factors of 8 which differ by 2

=# -3ap(x-4)(x+2)#

Related questions
See all questions in Factoring Completely
Impact of this question
924 views around the world
You can reuse this answer
Creative Commons License