How do you factor #-36n^2+48n-15#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Alan P. Sep 1, 2016 #-36n^2+48n-15=color(green)(-3(6n-5)(2n-1))# Explanation: #-36n^2+48n-15# #color(white)("XXX")=-(6n)^2+8(6n)-15# (replacing #6n# with #p# temporarily) #color(white)("XXX")=-p^2+8p-15# #color(white)("XXX")=(-1)(p-5)(p-3)# (restoring #6n# back in place of #p#) #color(white)("XXX")=(-1)(6n-5)(6n-3)# #color(white)("XXX")=(-3)(6n-5)(2n-1)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1404 views around the world You can reuse this answer Creative Commons License