How do you factor $2 x^{4} - 8 x^{3} - 11 x^{2} - 4 x - 6$ $2x^4-8x^3-11x^2-4x-6$ ?

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How do you factor $2 x^{4} - 8 x^{3} - 11 x^{2} - 4 x - 6$ $2x^4-8x^3-11x^2-4x-6$ ?

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Answer 1 · 2016-07-25T22:45:00

We have that

$2x^4-8x^3-11x^2-4x-6=2x^4-8x^3-(12-1)x^2-4x-6= 2x^4-8x^3-12x^2+x^2-4x-6=2x^2(x^2-4x-6)+(x^2-4x-6)= (x^2-4x-6)*(2x^2+1)=(x+sqrt10-2)*(x-sqrt10-2)*(2x^2+1)$

Footnote

We write $11=12-1$

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How do you factor $2 x^{4} - 8 x^{3} - 11 x^{2} - 4 x - 6$ $2x^4-8x^3-11x^2-4x-6$ ?

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