How do you factor #2x^4-8x^3-11x^2-4x-6#?

Question

How do you factor #2x^4-8x^3-11x^2-4x-6#?

1 Answer

Impact of this question

2699 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-25T22:45:00

We have that

#2x^4-8x^3-11x^2-4x-6=2x^4-8x^3-(12-1)x^2-4x-6= 2x^4-8x^3-12x^2+x^2-4x-6=2x^2(x^2-4x-6)+(x^2-4x-6)= (x^2-4x-6)*(2x^2+1)=(x+sqrt10-2)*(x-sqrt10-2)*(2x^2+1)#

Footnote

We write #11=12-1#

Science

Math

Humanities

... and beyond

How do you factor #2x^4-8x^3-11x^2-4x-6#?

1 Answer

Related questions

Impact of this question