How do you factor $2x^2 + 4x - 96$ ?

Question

2024 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-01T18:20:36

$2x^2+4x-96$

$=2(x^2+2x-48)$

Noting that $48$ has the obvious factor pair $(6,8)$ whose difference is $2$ (the coefficient of $x$ )

$=2(x+8)(x-6)$

How do you factor 2x^2 + 4x - 962x^2 + 4x - 96?