How do you factor #2x^2+4x+2#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Alan P. Jul 24, 2015 #2x^2+4x+1 = 2(x+1)^2# Explanation: #2x^2+4x+2# #color(white)("XXXX")#Extract the obvious constant factor #= 2(x^2+2x+1)# #color(white)("XXXX")#Recognize the "sum of squares" component #= 2(x+1)(x+1)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 9560 views around the world You can reuse this answer Creative Commons License