How do you factor $2m^3-2m^2+3-3m$ ?

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Answer 1 · 2015-04-29T23:46:41

Collect $2m^2$ between the first and second term and $-3$ between the third and fourth:
$2m^2(m-1)-3(m-1)$ and collect $(m-1)$ :
$(m-1)(2m^2-3)$

How do you factor 2m^3-2m^2+3-3m2m^3-2m^2+3-3m?