How do you factor $2 h^{3} + h^{2} - 18 h - 9$ $2h^3+h^2-18h-9$ by grouping?

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How do you factor $2 h^{3} + h^{2} - 18 h - 9$ $2h^3+h^2-18h-9$ by grouping?

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Answer 1 · 2016-07-30T08:59:24

$= (2 h + 1) (h + 3) (h - 3)$ $=(2h+1)(h+3)(h-3)$

Explanation:

$2 h^{3} + h^{2} - 18 h - 9$ $2h^3+h^2-18h-9$
$= h^{2} (2 h + 1) - 9 (2 h + 1)$ $=h^2(2h+1)-9(2h+1)$
$= (2 h + 1) (h^{2} - 9)$ $=(2h+1)(h^2-9)$
$= (2 h + 1) (h + 3) (h - 3)$ $=(2h+1)(h+3)(h-3)$

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How do you factor $2 h^{3} + h^{2} - 18 h - 9$ $2h^3+h^2-18h-9$ by grouping?

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How do you factor $2 h^{3} + h^{2} - 18 h - 9$ $2h^3+h^2-18h-9$ by grouping?