How do you factor $2a^2-9a+9$ by grouping?

Question

2159 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-02T11:34:17

$(a - 3) (2a - 3)$

$2a^2 - 9a + 9$

Note that;

$-9a = -6a -3a$

$-6 xx -3 = -18$

$2a^2 - 6a - 3a + 9$

$(2a^2 - 6a) (-3a + 9)$

$2a(a - 3) -3(a - 3)$

$(a - 3) (2a - 3)$

How do you factor 2a^2-9a+92a^2-9a+9 by grouping?