How do you factor $26x^3y^2-52x^2y^3-39x^3y^6$ ?

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Answer 1 · 2016-03-27T06:27:46

$13 x^2 y^2(2x-4y-3xy^4)$

From the given $26x^3y^2-52x^2y^3-39x^3y^6$

We determine the common monomial factor which is the greatest common factor

in detail, we start with the numerical value among 26, 52, 39. The greatest common factor is 13

For the variables $x^3y^2,x^2y^3,x^3y^6$ the greatest common factor is $x^2 y^2$

so the greatest common monomial factor $=13 x^2 y^2$

so to factor the expression completely

$13 x^2 y^2(2x-4y-3xy^4)$

God bless...I hope the explanation is useful.

How do you factor 26x^3y^2-52x^2y^3-39x^3y^626x^3y^2-52x^2y^3-39x^3y^6?