How do you factor #-24x^3 + 2x + 47x^2#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Alan P. May 26, 2015 Given #-24x^3+2x+47x^2# Extract the obvious common term #(-x)# and re-arrange in normal sequence: #= (-x)(24x^2-47x-2)# Recognize that #(-47) = (color(red)(24)xxcolor(blue)((-2))) +(color(red)(1)xxcolor(blue)(1))# #=(-x)(color(red)(24x+1))(color(blue)(1x-2))# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1288 views around the world You can reuse this answer Creative Commons License