How do you factor #-12x^2+27#?

1 Answer
Alan P.
Mar 17, 2017

#-3(2x-3)(2x+3)#

Explanation:

Given
#color(white)("XXX")-12x^2+27#

we can remove the obvious integer factor #(-3)# to get
#color(white)("XXX")(-3)(4x^2-9)#

then recognizing #(4x^2-9)# as the difference of squares: #((2x)^2-(3)^2)#
with factors #(2x-3)# and #(2x+3)#

we obtain the result given above.

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