How do you factor $10 x^{2} + 35 x - 4 x - 14$ $10x^2+35x-4x-14$ by grouping?

Question

How do you factor $10 x^{2} + 35 x - 4 x - 14$ $10x^2+35x-4x-14$ by grouping?

2 Answers

Impact of this question

2364 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-30T19:03:48

$10 x^{2} + 35 x - 4 x - 14 = (5 x - 2) (2 x + 7)$ $10x^2+35x-4x-14 = (5x-2)(2x+7)$

Explanation:

Note that $10 x^{2}$ $10x^2$ and $35 x$ $35x$ are both divisible by $5 x$ $5x$ and $4 x$ $4x$ and $14$ $14$ are both divisible by $2$ $2$ .

So we find:

$10 x^{2} + 35 x - 4 x - 14 = (10 x^{2} + 35 x) - (4 x + 14)$ $10x^2+35x-4x-14 = (10x^2+35x)-(4x+14)$

$10 x^{2} + 35 x - 4 x - 14 = 5 x (2 x + 7) - 2 (2 x + 7)$ $color(white)(10x^2+35x-4x-14) = 5x(2x+7)-2(2x+7)$

$10 x^{2} + 35 x - 4 x - 14 = (5 x - 2) (2 x + 7)$ $color(white)(10x^2+35x-4x-14) = (5x-2)(2x+7)$

Answer 2 · 2018-03-30T19:06:43

$10 x^{2} + 35 x - 4 x - 14$ $10x^2+35x−4x−14$

$\Rightarrow 5 x (2 x + 7) - 2 (2 x + 7)$ $=>5x(2x+7)−2(2x+7)$

$\Rightarrow (5 x - 2) (2 x + 7)$ $=>(5x−2)(2x+7)$

$d d$ $color(white)(dd$

Verification,

$(5 x - 2) (2 x + 7)$ $(5x−2)(2x+7)$

$\Rightarrow 5 x (2 x + 7) - 2 (2 x + 7)$ $=>5x(2x+7)−2(2x+7)$

$\Rightarrow 10 x^{2} + 35 x - 4 x - 14$ $=>10x^2+35x−4x−14$

Science

Math

Humanities

... and beyond

How do you factor $10 x^{2} + 35 x - 4 x - 14$ $10x^2+35x-4x-14$ by grouping?

2 Answers

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor 10x2+35x−4x−1410x^2+35x-4x-14 by grouping?

2 Answers

Explanation:

Related questions

Impact of this question

How do you factor $10 x^{2} + 35 x - 4 x - 14$ $10x^2+35x-4x-14$ by grouping?