How do you expand #(y+4)^2#? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer CW Sep 16, 2016 #y^2+8y+16# Explanation: #(y+4)^2 = (y+4)(y+4)# #= y(y+4)+4(y+4)# #=y^2+4y+4y+16# #=y^2+8y=16# Answer link Related questions What is Pascal's triangle? How do I find the #n#th row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand #(2x + y)^4#? How do I use Pascal's triangle to expand #(3a + b)^4#? How do I use Pascal's triangle to expand #(x + 2)^5#? How do I use Pascal's triangle to expand #(x - 1)^5#? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial #(a-b)^6#? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 4880 views around the world You can reuse this answer Creative Commons License