How do you expand #(x + 3)^6# using Pascal’s Triangle?

1 Answer
bp
Sep 14, 2015

In the expansion of #(x+y)^6# = #x^6 + 6x^5 y +15x^4 y^2 + 20 x^3 y^3 + 15 x^2 y^4 +6x y^5 +y^6#, put y=3 to get the required answer.

Explanation:

The 6th row of the Pascal triangle would give the coefficients of the expansion of #(x+y)^6#. The expansion is #x^6 + 6x^5 y +15x^4 y^2 + 20 x^3 y^3 + 15 x^2 y^4 +6x y^5 +y^6#.

In this expansion put y=3 to get the expansion #(x+3)^6#

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